#SQLServer – Where does my index live?

Today, I got asked by one of my DBA’s about a recently deployed database that seemed to have a lot of filegroups with only a few tables.Ā  He wanted to verify that one of the tables was correctly partition-aligned, as well as learn where all of the indexes for these tables were stored.Ā  After a quick search of the Internets, I was able to fashion the following script to help.Ā  The script below will find every index on every user table in a database, and then determine if it’s partitioned or not.Ā  If it’s partitioned, the scheme name is returned; if not, the filegroup name.Ā  The final column provides an XML list of filegroups (because schemes can span multiple filegroups) and file locations (because filegroups can span multiple files).

 WITH C AS ( SELECT ps.data_space_id
, f.name
, d.physical_name
FROM sys.filegroups f
JOIN sys.database_files d ON d.data_space_id = f.data_space_id
JOIN sys.destination_data_spaces dds ON dds.data_space_id = f.data_space_id
JOIN sys.partition_schemes ps ON ps.data_space_id = dds.partition_scheme_id
UNION
SELECT f.data_space_id
, f.name
, d.physical_name
FROM sys.filegroups f
JOIN sys.database_files d ON d.data_space_id = f.data_space_id
)
SELECT [ObjectName] = OBJECT_NAME(i.[object_id])
, [IndexID] = i.[index_id]
, [IndexName] = i.[name]
, [IndexType] = i.[type_desc]
, [Partitioned] = CASE WHEN ps.data_space_id IS NULL THEN 'No'
ELSE 'Yes'
END
, [StorageName] = ISNULL(ps.name, f.name)
, [FileGroupPaths] = CAST(( SELECT name AS "FileGroup"
, physical_name AS "DatabaseFile"
FROM C
WHERE i.data_space_id = c.data_space_id
FOR
XML PATH('')
) AS XML)
FROM [sys].[indexes] i
LEFT JOIN sys.partition_schemes ps ON ps.data_space_id = i.data_space_id
LEFT JOIN sys.filegroups f ON f.data_space_id = i.data_space_id
WHERE OBJECTPROPERTY(i.[object_id], 'IsUserTable') = 1
ORDER BY [ObjectName], [IndexName] 

August 14, 2014 Ā· stuart Ā· No Comments
Tags: , , , ,  Ā· Posted in: Code, SQL, SQL Server, SQLServerPedia Syndication, XML

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